2/n-6+1/n+2=3/n^2-4n-12

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Solution for 2/n-6+1/n+2=3/n^2-4n-12 equation: 



2/n-6+1/n+2=3/n^2-4n-12

We move all terms to the left:

2/n-6+1/n+2-(3/n^2-4n-12)=0



Domain of the equation: n!=0

n∈R





Domain of the equation: n^2-4n-12)!=0

n∈R



We add all the numbers together, and all the variables

2/n+1/n-(3/n^2-4n-12)-4=0

We get rid of parentheses

2/n+1/n-3/n^2+4n+12-4=0

We calculate fractions

We do not support enpression: n^3

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